\[y=f)x)\]

, defined between points \[x_1, \; x_2\]

is rotated about the \[x\]

axis, it forms a solid , called a volume or solid of revolution. The volume can be found by integration.\[V= \pi \int{x_2}_{x_1} y^2 dx \]

What though if the curve is rotated about some line other than an axis?

If the curve is rotated about a line parallel to the

\[y\]

axis, we can write a volume element as \[dV= \pi r^2dy\]

.Suppose the curve

\[y=x^2, \; 0 \lt x \lt 1\]

is rotated about the line \[x=1\]

. What is the volume of the solid formed?We can write

\[r=1-\sqrt{y}, \; 0 \lt y \lt 1\]

then the volume element becomes \[dV=(1- \sqrt{y})^2dy\]

. The solid of revolution has volume\[\begin{equation} \begin{aligned} V &= \pi \int^1_0 (1- \sqrt{y})^2dy \\ &= \int^1_0 (1-2 \sqrt{y}+y)dy \\ &= [y-\frac{2 \sqrt{y}}{3} + \frac{y^2}{2} ]^1_0 \\ &= (1- \frac{2}{3} + \frac{1}{2} )-(0) \\ &= \frac{5}{6}\end{aligned} \end{equation} \]