Proof of Equivalence of Continuity of Mapping of an Element of an Open Set to an Element of an Open Set



Thenis continuous if and only ifthere exists an open setwith

The converse is also true.


Supposeis continuous. Take anyand any open neighbourhoodof


Sinceis continuousSincewe have

Letrepresent an open set ofSupposethensois an open neighbourhood ofAn open setexists such thatand

Buthence for eachwhere

Henceis the union of open subsets ofand so is an open subset.

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