Theorem
Any countably compact subsetof a metric space
is also sequentially compact.
Proof
Letbe a metric space and let
be a sequence in
If the set
is finite then one of the elements, say
appears infinitely often, hence the subsequence
converges to
Suppose the setis infinite.
is countably compact. The infinite subset of
has an accumulation point
Since
is a metric space, we can choose a subsequence
which converges to
Hence
is sequentially compact.